Issolvi y=(3X+7)(X-1)^2V

$$y = ( 3 X + 7 ) ( X - 1 ) ^ { 2 } V$$

Solvi għal V

$$\left\{\begin{matrix}V=\frac{y}{\left(3X+7\right)\left(X-1\right)^{2}}\text{, }&X\neq 1\text{ and }X\neq -\frac{7}{3}\\V\in \mathrm{R}\text{, }&\left(X=-\frac{7}{3}\text{ or }X=1\right)\text{ and }y=0\end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(X-1\right)^{2}.

$$y=\left(3X+7\right)\left(X^{2}-2X+1\right)V$$

Uża l-propjetà distributtiva biex timmultiplika 3X+7 b'X^{2}-2X+1 u kkombina termini simili.

$$y=\left(3X^{3}+X^{2}-11X+7\right)V$$

Uża l-propjetà distributtiva biex timmultiplika 3X^{3}+X^{2}-11X+7 b'V.

$$y=3X^{3}V+X^{2}V-11XV+7V$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$3X^{3}V+X^{2}V-11XV+7V=y$$

Ikkombina t-termini kollha li fihom V.

$$\left(3X^{3}+X^{2}-11X+7\right)V=y$$

Iddividi ż-żewġ naħat b'3X^{3}+X^{2}-11X+7.

$$\frac{\left(3X^{3}+X^{2}-11X+7\right)V}{3X^{3}+X^{2}-11X+7}=\frac{y}{3X^{3}+X^{2}-11X+7}$$

Meta tiddividi b'3X^{3}+X^{2}-11X+7 titneħħa l-multiplikazzjoni b'3X^{3}+X^{2}-11X+7.

$$V=\frac{y}{3X^{3}+X^{2}-11X+7}$$

Iddividi y b'3X^{3}+X^{2}-11X+7.

$$V=\frac{y}{\left(3X+7\right)\left(X-1\right)^{2}}$$