Issolvi x+-25*3-45-1/2=-41/5

$$x+-25 \cdot 3-45- \frac{ 1 }{ 2 } = -4 \frac{ 1 }{ 5 }$$

Solvi għal x

$$x = \frac{1163}{10} = 116\frac{3}{10} = 116.3$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Immultiplika ż-żewġ naħat tal-ekwazzjoni b'10, l-inqas denominatur komuni ta' 2,5.

$$10x-250\times 3-450-5=-2\left(4\times 5+1\right)$$

Immultiplika -250 u 3 biex tikseb -750.

$$10x-750-450-5=-2\left(4\times 5+1\right)$$

Naqqas 450 minn -750 biex tikseb -1200.

$$10x-1200-5=-2\left(4\times 5+1\right)$$

Naqqas 5 minn -1200 biex tikseb -1205.

$$10x-1205=-2\left(4\times 5+1\right)$$

Immultiplika 4 u 5 biex tikseb 20.

$$10x-1205=-2\left(20+1\right)$$

Żid 20 u 1 biex tikseb 21.

$$10x-1205=-2\times 21$$

Immultiplika -2 u 21 biex tikseb -42.

$$10x-1205=-42$$

Żid 1205 maż-żewġ naħat.

$$10x=-42+1205$$

Żid -42 u 1205 biex tikseb 1163.

$$10x=1163$$

Iddividi ż-żewġ naħat b'10.

$$x=\frac{1163}{10}$$