Issolvi x_1^2-2-(x-0.8)=-2(0.9+x)

$$x _ { 1 } ^ { 2 } - 2 - ( x - 0.8 ) = - 2 ( 0.9 + x )$$

Solvi għal x

$$x=-\left(x_{1}^{2}+0.6\right)$$

Passi tas-Soluzzjonijiet

Biex issib l-oppost ta' x-0.8, sib l-oppost ta' kull terminu.

$$x_{1}^{2}-2-x+0.8=-2\left(0.9+x\right)$$

Żid -2 u 0.8 biex tikseb -1.2.

$$x_{1}^{2}-1.2-x=-2\left(0.9+x\right)$$

Uża l-propjetà distributtiva biex timmultiplika -2 b'0.9+x.

$$x_{1}^{2}-1.2-x=-1.8-2x$$

Żid 2x maż-żewġ naħat.

$$x_{1}^{2}-1.2-x+2x=-1.8$$

Ikkombina -x u 2x biex tikseb x.

$$x_{1}^{2}-1.2+x=-1.8$$

Naqqas x_{1}^{2} miż-żewġ naħat.

$$-1.2+x=-1.8-x_{1}^{2}$$

Żid 1.2 maż-żewġ naħat.

$$x=-1.8-x_{1}^{2}+1.2$$

Żid -1.8 u 1.2 biex tikseb -0.6.

$$x=-0.6-x_{1}^{2}$$

Solvi għal x_1 (complex solution)

$$x_{1}=-i\sqrt{x+0.6}$$

$$x_{1}=i\sqrt{x+0.6}$$

Solvi għal x_1

$$x_{1}=\frac{\sqrt{-4x-2.4}}{2}$$

$$x_{1}=-\frac{\sqrt{-4x-2.4}}{2}\text{, }x\leq -\frac{3}{5}$$