Issolvi j^2-9(x+y)^2

$$j ^ { 2 } - 9 ( x + y ) ^ { 2 }$$

Evalwa

$$-\left(3x+3y\right)^{2}+j^{2}$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+y\right)^{2}.

$$j^{2}-9\left(x^{2}+2xy+y^{2}\right)$$

Uża l-propjetà distributtiva biex timmultiplika -9 b'x^{2}+2xy+y^{2}.

$$j^{2}-9x^{2}-18xy-9y^{2}$$

Espandi

$$j^{2}-9y^{2}-18xy-9x^{2}$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+y\right)^{2}.

$$j^{2}-9\left(x^{2}+2xy+y^{2}\right)$$

Uża l-propjetà distributtiva biex timmultiplika -9 b'x^{2}+2xy+y^{2}.

$$j^{2}-9x^{2}-18xy-9y^{2}$$