Issolvi f(x)=3(x+6)^2-75

$$f ( x ) = 3 ( x + 6 ) ^ { 2 } - 75$$

Evalwa

$$3\left(x+1\right)\left(x+11\right)$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+6\right)^{2}.

$$3\left(x^{2}+12x+36\right)-75$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'x^{2}+12x+36.

$$3x^{2}+36x+108-75$$

Naqqas 75 minn 108 biex tikseb 33.

$$3x^{2}+36x+33$$

Espandi

$$3x^{2}+36x+33$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+6\right)^{2}.

$$3\left(x^{2}+12x+36\right)-75$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'x^{2}+12x+36.

$$3x^{2}+36x+108-75$$

Naqqas 75 minn 108 biex tikseb 33.

$$3x^{2}+36x+33$$