Issolvi f=a(1+cosθ)

$$f = a ( 1 + \cos \theta )$$

Solvi għal a

$$\left\{\begin{matrix}a=\frac{f}{\cos(\theta )+1}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}+\pi \\a\in \mathrm{R}\text{, }&f=0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}+\pi \end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika a b'1+\cos(\theta ).

$$f=a+a\cos(\theta )$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$a+a\cos(\theta )=f$$

Ikkombina t-termini kollha li fihom a.

$$\left(1+\cos(\theta )\right)a=f$$

L-ekwazzjoni hija f'forma standard.

$$\left(\cos(\theta )+1\right)a=f$$

Iddividi ż-żewġ naħat b'1+\cos(\theta ).

$$\frac{\left(\cos(\theta )+1\right)a}{\cos(\theta )+1}=\frac{f}{\cos(\theta )+1}$$

Meta tiddividi b'1+\cos(\theta ) titneħħa l-multiplikazzjoni b'1+\cos(\theta ).

$$a=\frac{f}{\cos(\theta )+1}$$

Solvi għal f

$$f=a\left(\cos(\theta )+1\right)$$