Issolvi c=(x+1)(2+x)-(x+1)(4x-8)

$$c = ( x + 1 ) ( 2 + x ) - ( x + 1 ) ( 4 x - 8 )$$

Solvi għal c

$$c=\left(10-3x\right)\left(x+1\right)$$

Passi tas-Soluzzjonijiet

Uża l-propjetà distributtiva biex timmultiplika x+1 b'2+x u kkombina termini simili.

$$c=3x+x^{2}+2-\left(x+1\right)\left(4x-8\right)$$

Uża l-propjetà distributtiva biex timmultiplika x+1 b'4x-8 u kkombina termini simili.

$$c=3x+x^{2}+2-\left(4x^{2}-4x-8\right)$$

Biex issib l-oppost ta' 4x^{2}-4x-8, sib l-oppost ta' kull terminu.

$$c=3x+x^{2}+2-4x^{2}+4x+8$$

Ikkombina x^{2} u -4x^{2} biex tikseb -3x^{2}.

$$c=3x-3x^{2}+2+4x+8$$

Ikkombina 3x u 4x biex tikseb 7x.

$$c=7x-3x^{2}+2+8$$

Żid 2 u 8 biex tikseb 10.

$$c=7x-3x^{2}+10$$

Solvi għal x (complex solution)

$$x=\frac{\sqrt{169-12c}+7}{6}$$

$$x=\frac{-\sqrt{169-12c}+7}{6}$$

Solvi għal x

$$x=\frac{\sqrt{169-12c}+7}{6}$$

$$x=\frac{-\sqrt{169-12c}+7}{6}\text{, }c\leq \frac{169}{12}$$