Issolvi c=1+tan(2pi/9)^2/sqrt{(4^2+1)}

$$c = \frac { 1 + \tan ( 2 \frac { \pi } { 9 } ) ^ { 2 } } { \sqrt { ( 4 ^ { 2 } + 1 ) } }$$

Solvi għal c

$$c=\frac{170408819104184715837886196294401\sqrt{17}}{1700000000000000000000000000000000}\approx 0.413302095$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Evaluate trigonometric functions in the problem

$$c = \frac{1 + 0.8390996311772799 ^ {2}}{\sqrt{{(4 ^ {2} + 1)}}}$$

Ikkalkula 0.8390996311772799 bil-power ta' 2 u tikseb 0.70408819104184715837886196294401.

$$c=\frac{1+0.70408819104184715837886196294401}{\sqrt{4^{2}+1}}$$

Żid 1 u 0.70408819104184715837886196294401 biex tikseb 1.70408819104184715837886196294401.

$$c=\frac{1.70408819104184715837886196294401}{\sqrt{4^{2}+1}}$$

Ikkalkula 4 bil-power ta' 2 u tikseb 16.

$$c=\frac{1.70408819104184715837886196294401}{\sqrt{16+1}}$$

Żid 16 u 1 biex tikseb 17.

$$c=\frac{1.70408819104184715837886196294401}{\sqrt{17}}$$

Irrazzjonalizza d-denominatur tal-\frac{1.70408819104184715837886196294401}{\sqrt{17}} billi timmultiplika in-numeratur u d-denominatur mill-\sqrt{17}.

$$c=\frac{1.70408819104184715837886196294401\sqrt{17}}{\left(\sqrt{17}\right)^{2}}$$

Il-kwadrat ta' \sqrt{17} huwa 17.

$$c=\frac{1.70408819104184715837886196294401\sqrt{17}}{17}$$

Iddividi 1.70408819104184715837886196294401\sqrt{17} b'17 biex tikseb\frac{170408819104184715837886196294401}{1700000000000000000000000000000000}\sqrt{17}.

$$c=\frac{170408819104184715837886196294401}{1700000000000000000000000000000000}\sqrt{17}$$

Assenja c

$$c≔\frac{170408819104184715837886196294401\sqrt{17}}{1700000000000000000000000000000000}$$