Issolvi a(-63)+beta(3-9)=c-2

$$a ( - 63 ) + \beta ( 3 - 9 ) = c - 2$$

Solvi għal a

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Naqqas 9 minn 3 biex tikseb -6.

$$a\left(-63\right)+\beta \left(-6\right)=c-2$$

Naqqas \beta \left(-6\right) miż-żewġ naħat.

$$a\left(-63\right)=c-2-\beta \left(-6\right)$$

Immultiplika -1 u -6 biex tikseb 6.

$$a\left(-63\right)=c-2+6\beta$$

L-ekwazzjoni hija f'forma standard.

$$-63a=c+6\beta -2$$

Iddividi ż-żewġ naħat b'-63.

$$\frac{-63a}{-63}=\frac{c+6\beta -2}{-63}$$

Meta tiddividi b'-63 titneħħa l-multiplikazzjoni b'-63.

$$a=\frac{c+6\beta -2}{-63}$$

Iddividi c-2+6\beta b'-63.

$$a=-\frac{c}{63}-\frac{2\beta }{21}+\frac{2}{63}$$

Solvi għal c

$$c=2-6\beta -63a$$