Issolvi F(x)=5x^2-(x+7/x^3-x

$$F ( x ) = \frac { 5 x ^ { 2 } - ( x + 7 } { x ^ { 3 } - x }$$

Solvi għal F

$$F=-\frac{7+x+5x^{3}-5x^{5}}{x^{2}\left(x^{2}-1\right)}$$

$$x\neq 0\text{ and }|x|\neq 1$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Immultiplika ż-żewġ naħat tal-ekwazzjoni b'x\left(x-1\right)\left(x+1\right).

$$Fxx\left(x-1\right)\left(x+1\right)=5x^{2}x\left(x-1\right)\left(x+1\right)-\left(x+7\right)$$

Immultiplika x u x biex tikseb x^{2}.

$$Fx^{2}\left(x-1\right)\left(x+1\right)=5x^{2}x\left(x-1\right)\left(x+1\right)-\left(x+7\right)$$

Uża l-propjetà distributtiva biex timmultiplika Fx^{2} b'x-1.

$$\left(Fx^{3}-Fx^{2}\right)\left(x+1\right)=5x^{2}x\left(x-1\right)\left(x+1\right)-\left(x+7\right)$$

Uża l-propjetà distributtiva biex timmultiplika Fx^{3}-Fx^{2} b'x+1 u kkombina termini simili.

$$Fx^{4}-Fx^{2}=5x^{2}x\left(x-1\right)\left(x+1\right)-\left(x+7\right)$$

Biex timmultiplika l-qawwa tal-istess bażi, żid l-esponenti tagħhom. Żid 2 u 1 biex tikseb 3.

$$Fx^{4}-Fx^{2}=5x^{3}\left(x-1\right)\left(x+1\right)-\left(x+7\right)$$

Uża l-propjetà distributtiva biex timmultiplika 5x^{3} b'x-1.

$$Fx^{4}-Fx^{2}=\left(5x^{4}-5x^{3}\right)\left(x+1\right)-\left(x+7\right)$$

Uża l-propjetà distributtiva biex timmultiplika 5x^{4}-5x^{3} b'x+1 u kkombina termini simili.

$$Fx^{4}-Fx^{2}=5x^{5}-5x^{3}-\left(x+7\right)$$

Biex issib l-oppost ta' x+7, sib l-oppost ta' kull terminu.

$$Fx^{4}-Fx^{2}=5x^{5}-5x^{3}-x-7$$

Ikkombina t-termini kollha li fihom F.

$$\left(x^{4}-x^{2}\right)F=5x^{5}-5x^{3}-x-7$$

Iddividi ż-żewġ naħat b'x^{4}-x^{2}.

$$\frac{\left(x^{4}-x^{2}\right)F}{x^{4}-x^{2}}=\frac{5x^{5}-5x^{3}-x-7}{x^{4}-x^{2}}$$

Meta tiddividi b'x^{4}-x^{2} titneħħa l-multiplikazzjoni b'x^{4}-x^{2}.

$$F=\frac{5x^{5}-5x^{3}-x-7}{x^{4}-x^{2}}$$

Iddividi 5x^{5}-5x^{3}-x-7 b'x^{4}-x^{2}.

$$F=\frac{5x^{5}-5x^{3}-x-7}{x^{2}\left(x^{2}-1\right)}$$