Issolvi C_{p}=h_{1}AtDeltaT

$$C _ { p } = h _ { 1 } A t \Delta T$$

Solvi għal A

$$\left\{\begin{matrix}A=\frac{C_{p}}{Th_{1}t\Delta }\text{, }&T\neq 0\text{ and }\Delta \neq 0\text{ and }t\neq 0\text{ and }h_{1}\neq 0\\A\in \mathrm{R}\text{, }&\left(T=0\text{ or }\Delta =0\text{ or }t=0\text{ or }h_{1}=0\right)\text{ and }C_{p}=0\end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$h_{1}At\Delta T=C_{p}$$

L-ekwazzjoni hija f'forma standard.

$$Th_{1}t\Delta A=C_{p}$$

Iddividi ż-żewġ naħat b'h_{1}t\Delta T.

$$\frac{Th_{1}t\Delta A}{Th_{1}t\Delta }=\frac{C_{p}}{Th_{1}t\Delta }$$

Meta tiddividi b'h_{1}t\Delta T titneħħa l-multiplikazzjoni b'h_{1}t\Delta T.

$$A=\frac{C_{p}}{Th_{1}t\Delta }$$

Solvi għal C_p

$$C_{p}=ATh_{1}t\Delta$$