Issolvi 56(x+11)=40+6(x+2

$$56 ( x + 11 ) = 40 + 6 ( x + 2$$

Solvi għal x

$$x = -\frac{282}{25} = -11\frac{7}{25} = -11.28$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 56 b'x+11.

$$56x+616=40+6\left(x+2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 6 b'x+2.

$$56x+616=40+6x+12$$

Żid 40 u 12 biex tikseb 52.

$$56x+616=52+6x$$

Naqqas 6x miż-żewġ naħat.

$$56x+616-6x=52$$

Ikkombina 56x u -6x biex tikseb 50x.

$$50x+616=52$$

Naqqas 616 miż-żewġ naħat.

$$50x=52-616$$

Naqqas 616 minn 52 biex tikseb -564.

$$50x=-564$$

Iddividi ż-żewġ naħat b'50.

$$x=\frac{-564}{50}$$

Naqqas il-frazzjoni \frac{-564}{50} għat-termini l-aktar baxxi billi testratta u tikkanċella barra 2.

$$x=-\frac{282}{25}$$