Issolvi 5(5x+8-4)<3(8x+7-4)+(2x+6x-9)-8(4x-7)

$$5 ( 5 x + 8 - 4 ) < 3 ( 8 x + 7 - 4 ) + ( 2 x + 6 x - 9 ) - 8 ( 4 x - 7 )$$

Solvi għal x

$$x<\frac{36}{25}$$

Passi tas-Soluzzjonijiet

Naqqas 4 minn 8 biex tikseb 4.

$$5\left(5x+4\right)<3\left(8x+7-4\right)+2x+6x-9-8\left(4x-7\right)$$

Uża l-propjetà distributtiva biex timmultiplika 5 b'5x+4.

$$25x+20<3\left(8x+7-4\right)+2x+6x-9-8\left(4x-7\right)$$

Naqqas 4 minn 7 biex tikseb 3.

$$25x+20<3\left(8x+3\right)+2x+6x-9-8\left(4x-7\right)$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'8x+3.

$$25x+20<24x+9+2x+6x-9-8\left(4x-7\right)$$

Ikkombina 24x u 2x biex tikseb 26x.

$$25x+20<26x+9+6x-9-8\left(4x-7\right)$$

Ikkombina 26x u 6x biex tikseb 32x.

$$25x+20<32x+9-9-8\left(4x-7\right)$$

Naqqas 9 minn 9 biex tikseb 0.

$$25x+20<32x-8\left(4x-7\right)$$

Uża l-propjetà distributtiva biex timmultiplika -8 b'4x-7.

$$25x+20<32x-32x+56$$

Ikkombina 32x u -32x biex tikseb 0.

$$25x+20<56$$

Naqqas 20 miż-żewġ naħat.

$$25x<56-20$$

Naqqas 20 minn 56 biex tikseb 36.

$$25x<36$$

Iddividi ż-żewġ naħat b'25. Peress li 25 huwa pożittiv, id-direzzjoni tal-inugwaljanza inbidlet.

$$x<\frac{36}{25}$$