Issolvi 5(2x-3)-2(4x-7)=4(x+10)

$$5 ( 2 x - 3 ) - 2 ( 4 x - 7 ) = 4 ( x + 10 )$$

Solvi għal x

$$x = -\frac{41}{2} = -20\frac{1}{2} = -20.5$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 5 b'2x-3.

$$10x-15-2\left(4x-7\right)=4\left(x+10\right)$$

Uża l-propjetà distributtiva biex timmultiplika -2 b'4x-7.

$$10x-15-8x+14=4\left(x+10\right)$$

Ikkombina 10x u -8x biex tikseb 2x.

$$2x-15+14=4\left(x+10\right)$$

Żid -15 u 14 biex tikseb -1.

$$2x-1=4\left(x+10\right)$$

Uża l-propjetà distributtiva biex timmultiplika 4 b'x+10.

$$2x-1=4x+40$$

Naqqas 4x miż-żewġ naħat.

$$2x-1-4x=40$$

Ikkombina 2x u -4x biex tikseb -2x.

$$-2x-1=40$$

Żid 1 maż-żewġ naħat.

$$-2x=40+1$$

Żid 40 u 1 biex tikseb 41.

$$-2x=41$$

Iddividi ż-żewġ naħat b'-2.

$$x=\frac{41}{-2}$$

Frazzjoni \frac{41}{-2} tista' tinkiteb mill-ġdid bħala -\frac{41}{2} bl-estrazzjoni tas-sinjal negattiv.

$$x=-\frac{41}{2}$$