Issolvi 5=(1.6*10^-4)(1+A)

$$5 = ( 1.6 \cdot 10 ^ { - 4 } ) ( 1 + A )$$

Solvi għal A

$$A=31249$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Ikkalkula 10 bil-power ta' -4 u tikseb \frac{1}{10000}.

$$5=1.6\times \frac{1}{10000}\left(1+A\right)$$

Immultiplika 1.6 u \frac{1}{10000} biex tikseb \frac{1}{6250}.

$$5=\frac{1}{6250}\left(1+A\right)$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{6250} b'1+A.

$$5=\frac{1}{6250}+\frac{1}{6250}A$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$\frac{1}{6250}+\frac{1}{6250}A=5$$

Naqqas \frac{1}{6250} miż-żewġ naħat.

$$\frac{1}{6250}A=5-\frac{1}{6250}$$

Naqqas \frac{1}{6250} minn 5 biex tikseb \frac{31249}{6250}.

$$\frac{1}{6250}A=\frac{31249}{6250}$$

Immultiplika ż-żewġ naħat b'6250, ir-reċiproku ta' \frac{1}{6250}.

$$A=\frac{31249}{6250}\times 6250$$

Immultiplika \frac{31249}{6250} u 6250 biex tikseb 31249.

$$A=31249$$