Issolvi 4000+100(x-12)=6400+(x-12)

$$4000 + 100 ( x - 12 ) = 6400 + ( x - 12 )$$

Solvi għal x

$$x = \frac{1196}{33} = 36\frac{8}{33} \approx 36.242424242$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 100 b'x-12.

$$4000+100x-1200=6400+x-12$$

Naqqas 1200 minn 4000 biex tikseb 2800.

$$2800+100x=6400+x-12$$

Naqqas 12 minn 6400 biex tikseb 6388.

$$2800+100x=6388+x$$

Naqqas x miż-żewġ naħat.

$$2800+100x-x=6388$$

Ikkombina 100x u -x biex tikseb 99x.

$$2800+99x=6388$$

Naqqas 2800 miż-żewġ naħat.

$$99x=6388-2800$$

Naqqas 2800 minn 6388 biex tikseb 3588.

$$99x=3588$$

Iddividi ż-żewġ naħat b'99.

$$x=\frac{3588}{99}$$

Naqqas il-frazzjoni \frac{3588}{99} għat-termini l-aktar baxxi billi testratta u tikkanċella barra 3.

$$x=\frac{1196}{33}$$