Issolvi 3x^2+(2k+1)x+3k-2=0

$$3 x ^ { 2 } + ( 2 k + 1 ) x + 3 k - 2 = 0$$

Solvi għal k

$$k=-\frac{\left(3x-2\right)\left(x+1\right)}{2x+3}$$

$$x\neq -\frac{3}{2}$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 2k+1 b'x.

$$3x^{2}+2kx+x+3k-2=0$$

Naqqas 3x^{2} miż-żewġ naħat. Xi ħaġa mnaqqsa minn żero tagħti numru negattiv.

$$2kx+x+3k-2=-3x^{2}$$

Naqqas x miż-żewġ naħat.

$$2kx+3k-2=-3x^{2}-x$$

Żid 2 maż-żewġ naħat.

$$2kx+3k=-3x^{2}-x+2$$

Ikkombina t-termini kollha li fihom k.

$$\left(2x+3\right)k=-3x^{2}-x+2$$

L-ekwazzjoni hija f'forma standard.

$$\left(2x+3\right)k=2-x-3x^{2}$$

Iddividi ż-żewġ naħat b'2x+3.

$$\frac{\left(2x+3\right)k}{2x+3}=-\frac{\left(3x-2\right)\left(x+1\right)}{2x+3}$$

Meta tiddividi b'2x+3 titneħħa l-multiplikazzjoni b'2x+3.

$$k=-\frac{\left(3x-2\right)\left(x+1\right)}{2x+3}$$

Solvi għal x (complex solution)

$$x=\frac{\sqrt{4k^{2}-32k+25}}{6}-\frac{k}{3}-\frac{1}{6}$$

$$x=-\frac{\sqrt{4k^{2}-32k+25}}{6}-\frac{k}{3}-\frac{1}{6}$$

Solvi għal x

$$x=\frac{\sqrt{4k^{2}-32k+25}}{6}-\frac{k}{3}-\frac{1}{6}$$

$$x=-\frac{\sqrt{4k^{2}-32k+25}}{6}-\frac{k}{3}-\frac{1}{6}\text{, }k\geq \frac{\sqrt{39}}{2}+4\text{ or }k\leq -\frac{\sqrt{39}}{2}+4$$