Issolvi 25000*(1+0.03/365)^x=1000000

$$25000 \times ( 1 + \frac { 0.03 } { 365 } ) ^ { x } = 1000000$$

Solvi għal x

$$x=\log_{\frac{36503}{36500}}\left(40\right)\approx 44883.211106122$$

Passi għall-Użu ta' Definizzjoni ta' Logaritmu

Iddividi ż-żewġ naħat b'25000.

$$\left(1+\frac{0.03}{365}\right)^{x}=\frac{1000000}{25000}$$

Iddividi 1000000 b'25000 biex tikseb40.

$$\left(1+\frac{0.03}{365}\right)^{x}=40$$

Espandi \frac{0.03}{365} billi timmultiplika kemm in-numeratur kif ukoll id-denominatur b'100.

$$\left(1+\frac{3}{36500}\right)^{x}=40$$

Żid 1 u \frac{3}{36500} biex tikseb \frac{36503}{36500}.

$$\left(\frac{36503}{36500}\right)^{x}=40$$

Ħu l-logaritmu taż-żewġ naħat tal-ekwazzjoni.

$$\log(\left(\frac{36503}{36500}\right)^{x})=\log(40)$$

Il-logaritmu ta ' numru imqajjem għall-enerġija hi l-qawwa ħinijiet Il-logaritmu tal-għadd.

$$x\log(\frac{36503}{36500})=\log(40)$$

Iddividi ż-żewġ naħat b'\log(\frac{36503}{36500}).

$$x=\frac{\log(40)}{\log(\frac{36503}{36500})}$$

Bil-formula bidla tal-bażi \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{\frac{36503}{36500}}\left(40\right)$$

Solvi għal x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(\frac{36503}{36500})}+\log_{\frac{36503}{36500}}\left(40\right)$$

$$n_{1}\in \mathrm{Z}$$