Issolvi 250*42*20=m*21*20+(m-50)*336

$$250 \times 42 \times 20 = m \times 21 \times 20 + ( m - 50 ) \times 336$$

Solvi għal m

$$m=300$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Immultiplika 250 u 42 biex tikseb 10500.

$$10500\times 20=m\times 21\times 20+\left(m-50\right)\times 336$$

Immultiplika 10500 u 20 biex tikseb 210000.

$$210000=m\times 21\times 20+\left(m-50\right)\times 336$$

Immultiplika 21 u 20 biex tikseb 420.

$$210000=m\times 420+\left(m-50\right)\times 336$$

Uża l-propjetà distributtiva biex timmultiplika m-50 b'336.

$$210000=m\times 420+336m-16800$$

Ikkombina m\times 420 u 336m biex tikseb 756m.

$$210000=756m-16800$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$756m-16800=210000$$

Żid 16800 maż-żewġ naħat.

$$756m=210000+16800$$

Żid 210000 u 16800 biex tikseb 226800.

$$756m=226800$$

Iddividi ż-żewġ naħat b'756.

$$m=\frac{226800}{756}$$

Iddividi 226800 b'756 biex tikseb300.

$$m=300$$