Issolvi 24+x=18sqrt{2}+sqrt{2}x

$$24+x=18 \sqrt{ 2 } + \sqrt{ 2 } x$$

Solvi għal x

$$x=6\left(\sqrt{2}-2\right)\approx -3.514718626$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Naqqas \sqrt{2}x miż-żewġ naħat.

$$24+x-\sqrt{2}x=18\sqrt{2}$$

Naqqas 24 miż-żewġ naħat.

$$x-\sqrt{2}x=18\sqrt{2}-24$$

Ikkombina t-termini kollha li fihom x.

$$\left(1-\sqrt{2}\right)x=18\sqrt{2}-24$$

Iddividi ż-żewġ naħat b'1-\sqrt{2}.

$$\frac{\left(1-\sqrt{2}\right)x}{1-\sqrt{2}}=\frac{18\sqrt{2}-24}{1-\sqrt{2}}$$

Meta tiddividi b'1-\sqrt{2} titneħħa l-multiplikazzjoni b'1-\sqrt{2}.

$$x=\frac{18\sqrt{2}-24}{1-\sqrt{2}}$$

Iddividi 18\sqrt{2}-24 b'1-\sqrt{2}.

$$x=6\sqrt{2}-12$$