Issolvi 2(m+1)x=3(m+1)(m-2)

$$2 ( m + 1 ) x = 3 ( m + 1 ) ( m - 2 )$$

Solvi għal x (complex solution)

$$\left\{\begin{matrix}\\x=\frac{3\left(m-2\right)}{2}\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&m=-1\end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 2 b'm+1.

$$\left(2m+2\right)x=3\left(m+1\right)\left(m-2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 2m+2 b'x.

$$2mx+2x=3\left(m+1\right)\left(m-2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'm+1.

$$2mx+2x=\left(3m+3\right)\left(m-2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 3m+3 b'm-2 u kkombina termini simili.

$$2mx+2x=3m^{2}-3m-6$$

Ikkombina t-termini kollha li fihom x.

$$\left(2m+2\right)x=3m^{2}-3m-6$$

Iddividi ż-żewġ naħat b'2m+2.

$$\frac{\left(2m+2\right)x}{2m+2}=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

Meta tiddividi b'2m+2 titneħħa l-multiplikazzjoni b'2m+2.

$$x=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

Iddividi 3\left(-2+m\right)\left(1+m\right) b'2m+2.

$$x=\frac{3m}{2}-3$$

Solvi għal x

$$\left\{\begin{matrix}\\x=\frac{3\left(m-2\right)}{2}\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&m=-1\end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 2 b'm+1.

$$\left(2m+2\right)x=3\left(m+1\right)\left(m-2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 2m+2 b'x.

$$2mx+2x=3\left(m+1\right)\left(m-2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'm+1.

$$2mx+2x=\left(3m+3\right)\left(m-2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 3m+3 b'm-2 u kkombina termini simili.

$$2mx+2x=3m^{2}-3m-6$$

Ikkombina t-termini kollha li fihom x.

$$\left(2m+2\right)x=3m^{2}-3m-6$$

Iddividi ż-żewġ naħat b'2m+2.

$$\frac{\left(2m+2\right)x}{2m+2}=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

Meta tiddividi b'2m+2 titneħħa l-multiplikazzjoni b'2m+2.

$$x=\frac{3\left(m-2\right)\left(m+1\right)}{2m+2}$$

Iddividi 3\left(-2+m\right)\left(1+m\right) b'2m+2.

$$x=\frac{3m}{2}-3$$

Solvi għal m

$$m=\frac{2\left(x+3\right)}{3}$$

$$m=-1$$