Issolvi 16+x^2=left(8-xright)^2

$$16+ { x }^{ 2 } = { \left(8-x \right) }^{ 2 }$$

Solvi għal x

$$x=3$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(8-x\right)^{2}.

$$16+x^{2}=64-16x+x^{2}$$

Żid 16x maż-żewġ naħat.

$$16+x^{2}+16x=64+x^{2}$$

Naqqas x^{2} miż-żewġ naħat.

$$16+x^{2}+16x-x^{2}=64$$

Ikkombina x^{2} u -x^{2} biex tikseb 0.

$$16+16x=64$$

Naqqas 16 miż-żewġ naħat.

$$16x=64-16$$

Naqqas 16 minn 64 biex tikseb 48.

$$16x=48$$

Iddividi ż-żewġ naħat b'16.

$$x=\frac{48}{16}$$

Iddividi 48 b'16 biex tikseb3.

$$x=3$$