Issolvi 12-0.6x=0.6left(x+10right)

$$12-0.6x = 0.6 \left( x+10 \right)$$

Solvi għal x

$$x=5$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 0.6 b'x+10.

$$12-0.6x=0.6x+6$$

Naqqas 0.6x miż-żewġ naħat.

$$12-0.6x-0.6x=6$$

Ikkombina -0.6x u -0.6x biex tikseb -1.2x.

$$12-1.2x=6$$

Naqqas 12 miż-żewġ naħat.

$$-1.2x=6-12$$

Naqqas 12 minn 6 biex tikseb -6.

$$-1.2x=-6$$

Iddividi ż-żewġ naħat b'-1.2.

$$x=\frac{-6}{-1.2}$$

Espandi \frac{-6}{-1.2} billi timmultiplika kemm in-numeratur kif ukoll id-denominatur b'10.

$$x=\frac{-60}{-12}$$

Iddividi -60 b'-12 biex tikseb5.

$$x=5$$