Issolvi 115=xleft(1+3.10^-3.50right)

$$115 = x \left( 1+3. { 10 }^{ -3 } .50 \right)$$

Solvi għal x

$$x = \frac{230000}{2003} = 114\frac{1658}{2003} \approx 114.827758362$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Ikkalkula 10 bil-power ta' -3 u tikseb \frac{1}{1000}.

$$115=x\left(1+3\times \frac{1}{1000}\times 0.5\right)$$

Immultiplika 3 u \frac{1}{1000} biex tikseb \frac{3}{1000}.

$$115=x\left(1+\frac{3}{1000}\times 0.5\right)$$

Immultiplika \frac{3}{1000} u 0.5 biex tikseb \frac{3}{2000}.

$$115=x\left(1+\frac{3}{2000}\right)$$

Żid 1 u \frac{3}{2000} biex tikseb \frac{2003}{2000}.

$$115=x\times \frac{2003}{2000}$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$x\times \frac{2003}{2000}=115$$

Immultiplika ż-żewġ naħat b'\frac{2000}{2003}, ir-reċiproku ta' \frac{2003}{2000}.

$$x=115\times \frac{2000}{2003}$$

Immultiplika 115 u \frac{2000}{2003} biex tikseb \frac{230000}{2003}.

$$x=\frac{230000}{2003}$$