Issolvi 112(1+a)^2=340.5

$$112 ( 1 + a ) ^ { 2 } = 340.5$$

Solvi għal a

$$a=\frac{\sqrt{9534}}{56}-1\approx 0.743610786$$

$$a=-\frac{\sqrt{9534}}{56}-1\approx -2.743610786$$

Passi billi Ssib l-Għerq Kwadrat

Iddividi ż-żewġ naħat b'112.

$$\frac{112\left(a+1\right)^{2}}{112}=\frac{340.5}{112}$$

Meta tiddividi b'112 titneħħa l-multiplikazzjoni b'112.

$$\left(a+1\right)^{2}=\frac{340.5}{112}$$

Iddividi 340.5 b'112.

$$\left(a+1\right)^{2}=\frac{681}{224}$$

Ħu l-għerq kwadrat taż-żewġ naħat tal-ekwazzjoni.

$$a+1=\frac{\sqrt{9534}}{56} a+1=-\frac{\sqrt{9534}}{56}$$

Naqqas 1 miż-żewġ naħat tal-ekwazzjoni.

$$a+1-1=\frac{\sqrt{9534}}{56}-1 a+1-1=-\frac{\sqrt{9534}}{56}-1$$

Jekk tnaqqas 1 minnu nnifsu jibqa' 0.

$$a=\frac{\sqrt{9534}}{56}-1 a=-\frac{\sqrt{9534}}{56}-1$$