Issolvi 10y-5(1+y)=3(2y-2)-20

$$10 y - 5 ( 1 + y ) = 3 ( 2 y - 2 ) - 20$$

Solvi għal y

$$y=21$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika -5 b'1+y.

$$10y-5-5y=3\left(2y-2\right)-20$$

Ikkombina 10y u -5y biex tikseb 5y.

$$5y-5=3\left(2y-2\right)-20$$

Uża l-propjetà distributtiva biex timmultiplika 3 b'2y-2.

$$5y-5=6y-6-20$$

Naqqas 20 minn -6 biex tikseb -26.

$$5y-5=6y-26$$

Naqqas 6y miż-żewġ naħat.

$$5y-5-6y=-26$$

Ikkombina 5y u -6y biex tikseb -y.

$$-y-5=-26$$

Żid 5 maż-żewġ naħat.

$$-y=-26+5$$

Żid -26 u 5 biex tikseb -21.

$$-y=-21$$

Immultiplika ż-żewġ naħat b'-1.

$$y=21$$