Issolvi 0.3(0.2x+1)=0.4(0.5x-1)

$$0.3 ( 0.2 x + 1 ) = 0.4 ( 0.5 x - 1 )$$

Solvi għal x

$$x=5$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 0.3 b'0.2x+1.

$$0.06x+0.3=0.4\left(0.5x-1\right)$$

Uża l-propjetà distributtiva biex timmultiplika 0.4 b'0.5x-1.

$$0.06x+0.3=0.2x-0.4$$

Naqqas 0.2x miż-żewġ naħat.

$$0.06x+0.3-0.2x=-0.4$$

Ikkombina 0.06x u -0.2x biex tikseb -0.14x.

$$-0.14x+0.3=-0.4$$

Naqqas 0.3 miż-żewġ naħat.

$$-0.14x=-0.4-0.3$$

Naqqas 0.3 minn -0.4 biex tikseb -0.7.

$$-0.14x=-0.7$$

Iddividi ż-żewġ naħat b'-0.14.

$$x=\frac{-0.7}{-0.14}$$

Espandi \frac{-0.7}{-0.14} billi timmultiplika kemm in-numeratur kif ukoll id-denominatur b'100.

$$x=\frac{-70}{-14}$$

Iddividi -70 b'-14 biex tikseb5.

$$x=5$$