Issolvi 0=2/2H125+10(125H-9375+260416)

$$0 = \frac { 2 } { 2 } H 125 + 10 ( 125 H - 9375 + 260416 )$$

Solvi għal H

$$H=-\frac{H_{125}}{1250}-\frac{251041}{125}$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Iddividi 2 b'2 biex tikseb1.

$$0=1H_{125}+10\left(125H-9375+260416\right)$$

Żid -9375 u 260416 biex tikseb 251041.

$$0=1H_{125}+10\left(125H+251041\right)$$

Uża l-propjetà distributtiva biex timmultiplika 10 b'125H+251041.

$$0=1H_{125}+1250H+2510410$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$1H_{125}+1250H+2510410=0$$

Naqqas 1H_{125} miż-żewġ naħat. Xi ħaġa mnaqqsa minn żero tagħti numru negattiv.

$$1250H+2510410=-H_{125}$$

Naqqas 2510410 miż-żewġ naħat.

$$1250H=-H_{125}-2510410$$

Iddividi ż-żewġ naħat b'1250.

$$\frac{1250H}{1250}=\frac{-H_{125}-2510410}{1250}$$

Meta tiddividi b'1250 titneħħa l-multiplikazzjoni b'1250.

$$H=\frac{-H_{125}-2510410}{1250}$$

Iddividi -H_{125}-2510410 b'1250.

$$H=-\frac{H_{125}}{1250}-\frac{251041}{125}$$

Solvi għal H_125

$$H_{125}=-1250H-2510410$$

Passi tas-Soluzzjonijiet

Iddividi 2 b'2 biex tikseb1.

$$0=1H_{125}+10\left(125H-9375+260416\right)$$

Żid -9375 u 260416 biex tikseb 251041.

$$0=1H_{125}+10\left(125H+251041\right)$$

Uża l-propjetà distributtiva biex timmultiplika 10 b'125H+251041.

$$0=1H_{125}+1250H+2510410$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$1H_{125}+1250H+2510410=0$$

Naqqas 1250H miż-żewġ naħat. Xi ħaġa mnaqqsa minn żero tagħti numru negattiv.

$$1H_{125}+2510410=-1250H$$

Naqqas 2510410 miż-żewġ naħat.

$$1H_{125}=-1250H-2510410$$

Erġa' ordna t-termini.

$$H_{125}=-1250H-2510410$$