Issolvi 0=2/2H125+10(12.5H-93.75+26.0416)

$$0 = \frac { 2 } { 2 } H 125 + 10 ( 12.5 H - 93.75 + 26.0416 )$$

Solvi għal H

$$H=-\frac{H_{125}}{125}+5.416672$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Iddividi 2 b'2 biex tikseb1.

$$0=1H_{125}+10\left(12.5H-93.75+26.0416\right)$$

Żid -93.75 u 26.0416 biex tikseb -67.7084.

$$0=1H_{125}+10\left(12.5H-67.7084\right)$$

Uża l-propjetà distributtiva biex timmultiplika 10 b'12.5H-67.7084.

$$0=1H_{125}+125H-677.084$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$1H_{125}+125H-677.084=0$$

Naqqas 1H_{125} miż-żewġ naħat. Xi ħaġa mnaqqsa minn żero tagħti numru negattiv.

$$125H-677.084=-H_{125}$$

Żid 677.084 maż-żewġ naħat.

$$125H=-H_{125}+677.084$$

L-ekwazzjoni hija f'forma standard.

$$125H=677.084-H_{125}$$

Iddividi ż-żewġ naħat b'125.

$$\frac{125H}{125}=\frac{677.084-H_{125}}{125}$$

Meta tiddividi b'125 titneħħa l-multiplikazzjoni b'125.

$$H=\frac{677.084-H_{125}}{125}$$

Iddividi -H_{125}+677.084 b'125.

$$H=-\frac{H_{125}}{125}+\frac{169271}{31250}$$

Solvi għal H_125

$$H_{125}=677.084-125H$$

Passi tas-Soluzzjonijiet

Iddividi 2 b'2 biex tikseb1.

$$0=1H_{125}+10\left(12.5H-93.75+26.0416\right)$$

Żid -93.75 u 26.0416 biex tikseb -67.7084.

$$0=1H_{125}+10\left(12.5H-67.7084\right)$$

Uża l-propjetà distributtiva biex timmultiplika 10 b'12.5H-67.7084.

$$0=1H_{125}+125H-677.084$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$1H_{125}+125H-677.084=0$$

Naqqas 125H miż-żewġ naħat. Xi ħaġa mnaqqsa minn żero tagħti numru negattiv.

$$1H_{125}-677.084=-125H$$

Żid 677.084 maż-żewġ naħat.

$$1H_{125}=-125H+677.084$$

Erġa' ordna t-termini.

$$H_{125}=-125H+677.084$$