Issolvi -1/2left(z-1right)+1/2left(z+1right)-1/2left(z-1right)^2-1/2left(z+1right)

Evalwa

Espandi

Kwizz

Polynomial

5 problemi simili għal:

Problemi Simili mit-Tiftix tal-Web

https://www.tiger-algebra.com/drill/((z-1)/(z_1))~3-2$((z-1)/(z_1))~2_((z-1)/(z_1))-2=0/

https://math.stackexchange.com/questions/2407074/solving-frac-partial2-u-partial2-t-c2-w2-u

https://math.stackexchange.com/questions/1261515/dog-bone-contour-integral

https://math.stackexchange.com/q/529280

Sehem

Ikkupjat fuq il-klibbord

-\frac{1}{2\left(z-1\right)}-\frac{1}{2\left(z-1\right)^{2}}

Naqqas \frac{1}{2\left(z+1\right)} minn \frac{1}{2\left(z+1\right)} biex tikseb 0.

-\frac{z-1}{2\left(z-1\right)^{2}}-\frac{1}{2\left(z-1\right)^{2}}

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' 2\left(z-1\right) u 2\left(z-1\right)^{2} huwa 2\left(z-1\right)^{2}. Immultiplika -\frac{1}{2\left(z-1\right)} b'\frac{z-1}{z-1}.

\frac{-\left(z-1\right)-1}{2\left(z-1\right)^{2}}

Billi -\frac{z-1}{2\left(z-1\right)^{2}} u \frac{1}{2\left(z-1\right)^{2}} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

\frac{-z+1-1}{2\left(z-1\right)^{2}}

Agħmel il-multiplikazzjonijiet fi -\left(z-1\right)-1.

\frac{-z}{2\left(z-1\right)^{2}}

Ikkombina termini simili f'-z+1-1.

\frac{-z}{2z^{2}-4z+2}

Espandi 2\left(z-1\right)^{2}.