Issolvi (y+2)(y+2)=16x

$$(y+2)(y+2)=16x$$

Solvi għal x

$$x=\frac{\left(y+2\right)^{2}}{16}$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Immultiplika y+2 u y+2 biex tikseb \left(y+2\right)^{2}.

$$\left(y+2\right)^{2}=16x$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(y+2\right)^{2}.

$$y^{2}+4y+4=16x$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$16x=y^{2}+4y+4$$

Iddividi ż-żewġ naħat b'16.

$$\frac{16x}{16}=\frac{\left(y+2\right)^{2}}{16}$$

Meta tiddividi b'16 titneħħa l-multiplikazzjoni b'16.

$$x=\frac{\left(y+2\right)^{2}}{16}$$

Solvi għal y (complex solution)

$$y=-4\sqrt{x}-2$$

$$y=4\sqrt{x}-2$$

Solvi għal y

$$y=-4\sqrt{x}-2$$

$$y=4\sqrt{x}-2\text{, }x\geq 0$$