Issolvi (9div5)(x+(7div2))=(129div20)+12x

$$(9 \div 5)(x+(7 \div 2))=(129 \div 20)+12x$$

Solvi għal x

$$x=-\frac{1}{68}\approx -0.014705882$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika \frac{9}{5} b'x+\frac{7}{2}.

$$\frac{9}{5}x+\frac{9}{5}\times \frac{7}{2}=\frac{129}{20}+12x$$

Immultiplika \frac{9}{5} b'\frac{7}{2} billi timmultiplika n-numeratur bin-numeratur u d-denominatur bid-denominatur.

$$\frac{9}{5}x+\frac{9\times 7}{5\times 2}=\frac{129}{20}+12x$$

Agħmel il-multiplikazzjonijiet fil-frazzjoni \frac{9\times 7}{5\times 2}.

$$\frac{9}{5}x+\frac{63}{10}=\frac{129}{20}+12x$$

Naqqas 12x miż-żewġ naħat.

$$\frac{9}{5}x+\frac{63}{10}-12x=\frac{129}{20}$$

Ikkombina \frac{9}{5}x u -12x biex tikseb -\frac{51}{5}x.

$$-\frac{51}{5}x+\frac{63}{10}=\frac{129}{20}$$

Naqqas \frac{63}{10} miż-żewġ naħat.

$$-\frac{51}{5}x=\frac{129}{20}-\frac{63}{10}$$

L-inqas multipli komuni ta' 20 u 10 huwa 20. Ikkonverti \frac{129}{20} u \frac{63}{10} fi frazzjonijiet bid-denominatur 20.

$$-\frac{51}{5}x=\frac{129}{20}-\frac{126}{20}$$

Billi \frac{129}{20} u \frac{126}{20} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$-\frac{51}{5}x=\frac{129-126}{20}$$

Naqqas 126 minn 129 biex tikseb 3.

$$-\frac{51}{5}x=\frac{3}{20}$$

Immultiplika ż-żewġ naħat b'-\frac{5}{51}, ir-reċiproku ta' -\frac{51}{5}.

$$x=\frac{3}{20}\left(-\frac{5}{51}\right)$$

Immultiplika \frac{3}{20} b'-\frac{5}{51} billi timmultiplika n-numeratur bin-numeratur u d-denominatur bid-denominatur.

$$x=\frac{3\left(-5\right)}{20\times 51}$$

Agħmel il-multiplikazzjonijiet fil-frazzjoni \frac{3\left(-5\right)}{20\times 51}.

$$x=\frac{-15}{1020}$$

Naqqas il-frazzjoni \frac{-15}{1020} għat-termini l-aktar baxxi billi testratta u tikkanċella barra 15.

$$x=-\frac{1}{68}$$