Issolvi (y-6)^2-(y+4)^2=0

$$( y - 6 ) ^ { 2 } - ( y + 4 ) ^ { 2 } = 0$$

Solvi għal y

$$y=1$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(y-6\right)^{2}.

$$y^{2}-12y+36-\left(y+4\right)^{2}=0$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(y+4\right)^{2}.

$$y^{2}-12y+36-\left(y^{2}+8y+16\right)=0$$

Biex issib l-oppost ta' y^{2}+8y+16, sib l-oppost ta' kull terminu.

$$y^{2}-12y+36-y^{2}-8y-16=0$$

Ikkombina y^{2} u -y^{2} biex tikseb 0.

$$-12y+36-8y-16=0$$

Ikkombina -12y u -8y biex tikseb -20y.

$$-20y+36-16=0$$

Naqqas 16 minn 36 biex tikseb 20.

$$-20y+20=0$$

Naqqas 20 miż-żewġ naħat. Xi ħaġa mnaqqsa minn żero tagħti numru negattiv.

$$-20y=-20$$

Iddividi ż-żewġ naħat b'-20.

$$y=\frac{-20}{-20}$$

Iddividi -20 b'-20 biex tikseb1.

$$y=1$$