Issolvi (x-1)^2=-y+10/3

$$( x - 1 ) ^ { 2 } = - y + \frac { 10 } { 3 }$$

Solvi għal y

$$y=-\left(x-1\right)^{2}+\frac{10}{3}$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(x-1\right)^{2}.

$$x^{2}-2x+1=-y+\frac{10}{3}$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$-y+\frac{10}{3}=x^{2}-2x+1$$

Naqqas \frac{10}{3} miż-żewġ naħat.

$$-y=x^{2}-2x+1-\frac{10}{3}$$

Naqqas \frac{10}{3} minn 1 biex tikseb -\frac{7}{3}.

$$-y=x^{2}-2x-\frac{7}{3}$$

Iddividi ż-żewġ naħat b'-1.

$$\frac{-y}{-1}=\frac{x^{2}-2x-\frac{7}{3}}{-1}$$

Meta tiddividi b'-1 titneħħa l-multiplikazzjoni b'-1.

$$y=\frac{x^{2}-2x-\frac{7}{3}}{-1}$$

Iddividi x^{2}-2x-\frac{7}{3} b'-1.

$$y=\frac{7}{3}+2x-x^{2}$$

Solvi għal x (complex solution)

$$x=-\frac{\sqrt{30-9y}}{3}+1$$

$$x=\frac{\sqrt{30-9y}}{3}+1$$

Solvi għal x

$$x=-\frac{\sqrt{30-9y}}{3}+1$$

$$x=\frac{\sqrt{30-9y}}{3}+1\text{, }y\leq \frac{10}{3}$$