Issolvi (x+1)^2-(x-1)^2=8

$$( x + 1 ) ^ { 2 } - ( x - 1 ) ^ { 2 } = 8$$

Solvi għal x

$$x=2$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+1\right)^{2}.

$$x^{2}+2x+1-\left(x-1\right)^{2}=8$$

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(x-1\right)^{2}.

$$x^{2}+2x+1-\left(x^{2}-2x+1\right)=8$$

Biex issib l-oppost ta' x^{2}-2x+1, sib l-oppost ta' kull terminu.

$$x^{2}+2x+1-x^{2}+2x-1=8$$

Ikkombina x^{2} u -x^{2} biex tikseb 0.

$$2x+1+2x-1=8$$

Ikkombina 2x u 2x biex tikseb 4x.

$$4x+1-1=8$$

Naqqas 1 minn 1 biex tikseb 0.

$$4x=8$$

Iddividi ż-żewġ naħat b'4.

$$x=\frac{8}{4}$$

Iddividi 8 b'4 biex tikseb2.

$$x=2$$