Issolvi (x+1)^2=-25(y-1)

$$( x + 1 ) ^ { 2 } = - 25 ( y - 1 )$$

Solvi għal y

$$y=-\frac{\left(x-4\right)\left(x+6\right)}{25}$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+1\right)^{2}.

$$x^{2}+2x+1=-25\left(y-1\right)$$

Uża l-propjetà distributtiva biex timmultiplika -25 b'y-1.

$$x^{2}+2x+1=-25y+25$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$-25y+25=x^{2}+2x+1$$

Naqqas 25 miż-żewġ naħat.

$$-25y=x^{2}+2x+1-25$$

Naqqas 25 minn 1 biex tikseb -24.

$$-25y=x^{2}+2x-24$$

Iddividi ż-żewġ naħat b'-25.

$$\frac{-25y}{-25}=\frac{\left(x-4\right)\left(x+6\right)}{-25}$$

Meta tiddividi b'-25 titneħħa l-multiplikazzjoni b'-25.

$$y=\frac{\left(x-4\right)\left(x+6\right)}{-25}$$

Iddividi \left(-4+x\right)\left(6+x\right) b'-25.

$$y=-\frac{\left(x-4\right)\left(x+6\right)}{25}$$

Solvi għal x (complex solution)

$$x=-5\sqrt{1-y}-1$$

$$x=5\sqrt{1-y}-1$$

Solvi għal x

$$x=-5\sqrt{1-y}-1$$

$$x=5\sqrt{1-y}-1\text{, }y\leq 1$$