Issolvi (t-4)^2=(t+4)^2+3=

$$( t - 4 ) ^ { 2 } = ( t + 4 ) ^ { 2 } + 3 =$$

Solvi għal t

$$t=-\frac{3}{16}=-0.1875$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(t-4\right)^{2}.

$$t^{2}-8t+16=\left(t+4\right)^{2}+3$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(t+4\right)^{2}.

$$t^{2}-8t+16=t^{2}+8t+16+3$$

Żid 16 u 3 biex tikseb 19.

$$t^{2}-8t+16=t^{2}+8t+19$$

Naqqas t^{2} miż-żewġ naħat.

$$t^{2}-8t+16-t^{2}=8t+19$$

Ikkombina t^{2} u -t^{2} biex tikseb 0.

$$-8t+16=8t+19$$

Naqqas 8t miż-żewġ naħat.

$$-8t+16-8t=19$$

Ikkombina -8t u -8t biex tikseb -16t.

$$-16t+16=19$$

Naqqas 16 miż-żewġ naħat.

$$-16t=19-16$$

Naqqas 16 minn 19 biex tikseb 3.

$$-16t=3$$

Iddividi ż-żewġ naħat b'-16.

$$t=\frac{3}{-16}$$

Frazzjoni \frac{3}{-16} tista' tinkiteb mill-ġdid bħala -\frac{3}{16} bl-estrazzjoni tas-sinjal negattiv.

$$t=-\frac{3}{16}$$