Issolvi (5t-1)^2+(2t-2)(-t+4)

$$( 5 t - 1 ) ^ { 2 } + ( 2 t - 2 ) ( - t + 4 )$$

Evalwa

$$23t^{2}-7$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(5t-1\right)^{2}.

$$25t^{2}-10t+1+\left(2t-2\right)\left(-t+4\right)$$

Uża l-propjetà distributtiva biex timmultiplika 2t-2 b'-t+4.

$$25t^{2}-10t+1+2t\left(-t\right)+8t-2\left(-t\right)-8$$

Immultiplika -2 u -1 biex tikseb 2.

$$25t^{2}-10t+1+2t\left(-t\right)+8t+2t-8$$

Ikkombina 8t u 2t biex tikseb 10t.

$$25t^{2}-10t+1+2t\left(-t\right)+10t-8$$

Ikkombina -10t u 10t biex tikseb 0.

$$25t^{2}+1+2t\left(-t\right)-8$$

Naqqas 8 minn 1 biex tikseb -7.

$$25t^{2}-7+2t\left(-t\right)$$

Immultiplika t u t biex tikseb t^{2}.

$$25t^{2}-7+2t^{2}\left(-1\right)$$

Immultiplika 2 u -1 biex tikseb -2.

$$25t^{2}-7-2t^{2}$$

Ikkombina 25t^{2} u -2t^{2} biex tikseb 23t^{2}.

$$23t^{2}-7$$

Espandi

$$23t^{2}-7$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(5t-1\right)^{2}.

$$25t^{2}-10t+1+\left(2t-2\right)\left(-t+4\right)$$

Uża l-propjetà distributtiva biex timmultiplika 2t-2 b'-t+4.

$$25t^{2}-10t+1+2t\left(-t\right)+8t-2\left(-t\right)-8$$

Immultiplika -2 u -1 biex tikseb 2.

$$25t^{2}-10t+1+2t\left(-t\right)+8t+2t-8$$

Ikkombina 8t u 2t biex tikseb 10t.

$$25t^{2}-10t+1+2t\left(-t\right)+10t-8$$

Ikkombina -10t u 10t biex tikseb 0.

$$25t^{2}+1+2t\left(-t\right)-8$$

Naqqas 8 minn 1 biex tikseb -7.

$$25t^{2}-7+2t\left(-t\right)$$

Immultiplika t u t biex tikseb t^{2}.

$$25t^{2}-7+2t^{2}\left(-1\right)$$

Immultiplika 2 u -1 biex tikseb -2.

$$25t^{2}-7-2t^{2}$$

Ikkombina 25t^{2} u -2t^{2} biex tikseb 23t^{2}.

$$23t^{2}-7$$