Issolvi (3x+1)(x-1)-3(x+3)^2=-9

$$( 3 x + 1 ) ( x - 1 ) - 3 ( x + 3 ) ^ { 2 } = - 9$$

Solvi għal x

$$x=-\frac{19}{20}=-0.95$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 3x+1 b'x-1 u kkombina termini simili.

$$3x^{2}-2x-1-3\left(x+3\right)^{2}=-9$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+3\right)^{2}.

$$3x^{2}-2x-1-3\left(x^{2}+6x+9\right)=-9$$

Uża l-propjetà distributtiva biex timmultiplika -3 b'x^{2}+6x+9.

$$3x^{2}-2x-1-3x^{2}-18x-27=-9$$

Ikkombina 3x^{2} u -3x^{2} biex tikseb 0.

$$-2x-1-18x-27=-9$$

Ikkombina -2x u -18x biex tikseb -20x.

$$-20x-1-27=-9$$

Naqqas 27 minn -1 biex tikseb -28.

$$-20x-28=-9$$

Żid 28 maż-żewġ naħat.

$$-20x=-9+28$$

Żid -9 u 28 biex tikseb 19.

$$-20x=19$$

Iddividi ż-żewġ naħat b'-20.

$$x=\frac{19}{-20}$$

Frazzjoni \frac{19}{-20} tista' tinkiteb mill-ġdid bħala -\frac{19}{20} bl-estrazzjoni tas-sinjal negattiv.

$$x=-\frac{19}{20}$$