Issolvi (3*(-3a-1)-10a+19=7*(2-3a)+12

$$( 3 \cdot ( - 3 a - 1 ) - 10 a + 19 = 7 \cdot ( 2 - 3 a ) + 12$$

Solvi għal a

$$a=5$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża l-propjetà distributtiva biex timmultiplika 3 b'-3a-1.

$$-9a-3-10a+19=7\left(2-3a\right)+12$$

Ikkombina -9a u -10a biex tikseb -19a.

$$-19a-3+19=7\left(2-3a\right)+12$$

Żid -3 u 19 biex tikseb 16.

$$-19a+16=7\left(2-3a\right)+12$$

Uża l-propjetà distributtiva biex timmultiplika 7 b'2-3a.

$$-19a+16=14-21a+12$$

Żid 14 u 12 biex tikseb 26.

$$-19a+16=26-21a$$

Żid 21a maż-żewġ naħat.

$$-19a+16+21a=26$$

Ikkombina -19a u 21a biex tikseb 2a.

$$2a+16=26$$

Naqqas 16 miż-żewġ naħat.

$$2a=26-16$$

Naqqas 16 minn 26 biex tikseb 10.

$$2a=10$$

Iddividi ż-żewġ naħat b'2.

$$a=\frac{10}{2}$$

Iddividi 10 b'2 biex tikseb5.

$$a=5$$