( 2 v ( v - 7 ) = 5 v ( r - 7 )
Solvi għal r (complex solution)
\left\{\begin{matrix}\\r=\frac{2v+21}{5}\text{, }&\text{unconditionally}\\r\in \mathrm{C}\text{, }&v=0\end{matrix}\right.
Solvi għal r
\left\{\begin{matrix}\\r=\frac{2v+21}{5}\text{, }&\text{unconditionally}\\r\in \mathrm{R}\text{, }&v=0\end{matrix}\right.
Solvi għal v
v=\frac{5r-21}{2}
v=0
Sehem
Ikkupjat fuq il-klibbord
2v^{2}-14v=5v\left(r-7\right)
Uża l-propjetà distributtiva biex timmultiplika 2v b'v-7.
2v^{2}-14v=5vr-35v
Uża l-propjetà distributtiva biex timmultiplika 5v b'r-7.
5vr-35v=2v^{2}-14v
Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.
5vr=2v^{2}-14v+35v
Żid 35v maż-żewġ naħat.
5vr=2v^{2}+21v
Ikkombina -14v u 35v biex tikseb 21v.
\frac{5vr}{5v}=\frac{v\left(2v+21\right)}{5v}
Iddividi ż-żewġ naħat b'5v.
r=\frac{v\left(2v+21\right)}{5v}
Meta tiddividi b'5v titneħħa l-multiplikazzjoni b'5v.
r=\frac{2v+21}{5}
Iddividi v\left(21+2v\right) b'5v.
2v^{2}-14v=5v\left(r-7\right)
Uża l-propjetà distributtiva biex timmultiplika 2v b'v-7.
2v^{2}-14v=5vr-35v
Uża l-propjetà distributtiva biex timmultiplika 5v b'r-7.
5vr-35v=2v^{2}-14v
Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.
5vr=2v^{2}-14v+35v
Żid 35v maż-żewġ naħat.
5vr=2v^{2}+21v
Ikkombina -14v u 35v biex tikseb 21v.
\frac{5vr}{5v}=\frac{v\left(2v+21\right)}{5v}
Iddividi ż-żewġ naħat b'5v.
r=\frac{v\left(2v+21\right)}{5v}
Meta tiddividi b'5v titneħħa l-multiplikazzjoni b'5v.
r=\frac{2v+21}{5}
Iddividi v\left(21+2v\right) b'5v.
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