Issolvi (-2)^4=(-22/3)^2+51/2*(-1/6)-1/4

$$( - 2 ) ^ { 4 } = ( - 2 \frac { 2 } { 3 } ) ^ { 2 } + 5 \frac { 1 } { 2 } \times ( - \frac { 1 } { 6 } ) - \frac { 1 } { 4 }$$

Ivverifika

Passi tas-Soluzzjonijiet

Immultiplika ż-żewġ naħat tal-ekwazzjoni b'12, l-inqas denominatur komuni ta' 2,6,4.

$$12\left(-2\right)^{4}=12\left(-\frac{2\times 3+2}{3}\right)^{2}+6\left(5\times 2+1\right)\left(-\frac{1}{6}\right)-3$$

Ikkalkula -2 bil-power ta' 4 u tikseb 16.

$$12\times 16=12\left(-\frac{2\times 3+2}{3}\right)^{2}+6\left(5\times 2+1\right)\left(-\frac{1}{6}\right)-3$$

Immultiplika 12 u 16 biex tikseb 192.

$$192=12\left(-\frac{2\times 3+2}{3}\right)^{2}+6\left(5\times 2+1\right)\left(-\frac{1}{6}\right)-3$$

Immultiplika 2 u 3 biex tikseb 6.

$$192=12\left(-\frac{6+2}{3}\right)^{2}+6\left(5\times 2+1\right)\left(-\frac{1}{6}\right)-3$$

Żid 6 u 2 biex tikseb 8.

$$192=12\left(-\frac{8}{3}\right)^{2}+6\left(5\times 2+1\right)\left(-\frac{1}{6}\right)-3$$

Ikkalkula -\frac{8}{3} bil-power ta' 2 u tikseb \frac{64}{9}.

$$192=12\times \frac{64}{9}+6\left(5\times 2+1\right)\left(-\frac{1}{6}\right)-3$$

Immultiplika 12 u \frac{64}{9} biex tikseb \frac{256}{3}.

$$192=\frac{256}{3}+6\left(5\times 2+1\right)\left(-\frac{1}{6}\right)-3$$

Immultiplika 5 u 2 biex tikseb 10.

$$192=\frac{256}{3}+6\left(10+1\right)\left(-\frac{1}{6}\right)-3$$

Żid 10 u 1 biex tikseb 11.

$$192=\frac{256}{3}+6\times 11\left(-\frac{1}{6}\right)-3$$

Immultiplika 6 u 11 biex tikseb 66.

$$192=\frac{256}{3}+66\left(-\frac{1}{6}\right)-3$$

Immultiplika 66 u -\frac{1}{6} biex tikseb -11.

$$192=\frac{256}{3}-11-3$$

Naqqas 11 minn \frac{256}{3} biex tikseb \frac{223}{3}.

$$192=\frac{223}{3}-3$$

Naqqas 3 minn \frac{223}{3} biex tikseb \frac{214}{3}.

$$192=\frac{214}{3}$$

Ikkonverti 192 fi frazzjoni \frac{576}{3}.

$$\frac{576}{3}=\frac{214}{3}$$

Qabbel \frac{576}{3} u \frac{214}{3}.

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