Issolvi -1^3-3*-1+2=1-3+2=0

$${ -1 }^{ 3 } -3 \cdot -1+2 = 1-3+2=0$$

Ivverifika

Passi tas-Soluzzjonijiet

Ikkalkula -1 bil-power ta' 3 u tikseb -1.

$$-1-3\left(-1\right)+2=1-3+2\text{ and }1-3+2=0$$

Immultiplika 3 u -1 biex tikseb -3.

$$-1-\left(-3\right)+2=1-3+2\text{ and }1-3+2=0$$

L-oppost ta' -3 huwa 3.

$$-1+3+2=1-3+2\text{ and }1-3+2=0$$

Żid -1 u 3 biex tikseb 2.

$$2+2=1-3+2\text{ and }1-3+2=0$$

Żid 2 u 2 biex tikseb 4.

$$4=1-3+2\text{ and }1-3+2=0$$

Naqqas 3 minn 1 biex tikseb -2.

$$4=-2+2\text{ and }1-3+2=0$$

Żid -2 u 2 biex tikseb 0.

$$4=0\text{ and }1-3+2=0$$

Qabbel 4 u 0.

$$\text{false}\text{ and }1-3+2=0$$

Naqqas 3 minn 1 biex tikseb -2.

$$\text{false}\text{ and }-2+2=0$$

Żid -2 u 2 biex tikseb 0.

$$\text{false}\text{ and }0=0$$

Qabbel 0 u 0.

$$\text{false}\text{ and }\text{true}$$

Il-conjunction ta' \text{false} u \text{true} hija \text{false}.

$$\text{false}$$