Issolvi left(y-5right)^2=-6(x+2)

$${ \left(y-5 \right) }^{ 2 } =-6(x+2)$$

Solvi għal x

$$x=-\frac{\left(y-5\right)^{2}}{6}-2$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(y-5\right)^{2}.

$$y^{2}-10y+25=-6\left(x+2\right)$$

Uża l-propjetà distributtiva biex timmultiplika -6 b'x+2.

$$y^{2}-10y+25=-6x-12$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$-6x-12=y^{2}-10y+25$$

Żid 12 maż-żewġ naħat.

$$-6x=y^{2}-10y+25+12$$

Żid 25 u 12 biex tikseb 37.

$$-6x=y^{2}-10y+37$$

Iddividi ż-żewġ naħat b'-6.

$$\frac{-6x}{-6}=\frac{y^{2}-10y+37}{-6}$$

Meta tiddividi b'-6 titneħħa l-multiplikazzjoni b'-6.

$$x=\frac{y^{2}-10y+37}{-6}$$

Iddividi y^{2}-10y+37 b'-6.

$$x=-\frac{y^{2}}{6}+\frac{5y}{3}-\frac{37}{6}$$

Solvi għal y (complex solution)

$$y=-\sqrt{-6x-12}+5$$

$$y=\sqrt{-6x-12}+5$$

Solvi għal y

$$y=-\sqrt{-6x-12}+5$$

$$y=\sqrt{-6x-12}+5\text{, }x\leq -2$$