Issolvi left(x+5right)^2=-20(y-95)

$${ \left(x+5 \right) }^{ 2 } =-20(y-95)$$

Solvi għal y

$$y=-\frac{\left(x+5\right)^{2}}{20}+95$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+5\right)^{2}.

$$x^{2}+10x+25=-20\left(y-95\right)$$

Uża l-propjetà distributtiva biex timmultiplika -20 b'y-95.

$$x^{2}+10x+25=-20y+1900$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$-20y+1900=x^{2}+10x+25$$

Naqqas 1900 miż-żewġ naħat.

$$-20y=x^{2}+10x+25-1900$$

Naqqas 1900 minn 25 biex tikseb -1875.

$$-20y=x^{2}+10x-1875$$

Iddividi ż-żewġ naħat b'-20.

$$\frac{-20y}{-20}=\frac{x^{2}+10x-1875}{-20}$$

Meta tiddividi b'-20 titneħħa l-multiplikazzjoni b'-20.

$$y=\frac{x^{2}+10x-1875}{-20}$$

Iddividi x^{2}+10x-1875 b'-20.

$$y=-\frac{x^{2}}{20}-\frac{x}{2}+\frac{375}{4}$$

Solvi għal x (complex solution)

$$x=-2\sqrt{475-5y}-5$$

$$x=2\sqrt{475-5y}-5$$

Solvi għal x

$$x=-2\sqrt{475-5y}-5$$

$$x=2\sqrt{475-5y}-5\text{, }y\leq 95$$