Issolvi {left(3sqrt{6}-2right)}^2+12sqrt{6}

$${ \left(3 \sqrt{ 6 } -2 \right) }^{ 2 } +12 \sqrt{ 6 }$$

Evalwa

$$58$$

Passi tas-Soluzzjonijiet

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(3\sqrt{6}-2\right)^{2}.

$$9\left(\sqrt{6}\right)^{2}-12\sqrt{6}+4+12\sqrt{6}$$

Il-kwadrat ta' \sqrt{6} huwa 6.

$$9\times 6-12\sqrt{6}+4+12\sqrt{6}$$

Immultiplika 9 u 6 biex tikseb 54.

$$54-12\sqrt{6}+4+12\sqrt{6}$$

Żid 54 u 4 biex tikseb 58.

$$58-12\sqrt{6}+12\sqrt{6}$$

Ikkombina -12\sqrt{6} u 12\sqrt{6} biex tikseb 0.

$$58$$

Fattur

$$2\times 29$$