Issolvi sqrt{2}*(sqrt{6}+sqrt{2})

$$\sqrt{ 2 } \times ( \sqrt{ 6 } + \sqrt{ 2 } )$$

Evalwa

$$2\left(\sqrt{3}+1\right)\approx 5.464101615$$

Passi tas-Soluzzjonijiet

Uża l-propjetà distributtiva biex timmultiplika \sqrt{2} b'\sqrt{6}+\sqrt{2}.

$$\sqrt{2}\sqrt{6}+\left(\sqrt{2}\right)^{2}$$

Iffattura 6=2\times 3. Erġa' ikteb l-għerq kwadrat tal-prodott \sqrt{2\times 3} bħala l-prodott tal-għeruq kwadrati \sqrt{2}\sqrt{3}.

$$\sqrt{2}\sqrt{2}\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

Immultiplika \sqrt{2} u \sqrt{2} biex tikseb 2.

$$2\sqrt{3}+\left(\sqrt{2}\right)^{2}$$

Il-kwadrat ta' \sqrt{2} huwa 2.

$$2\sqrt{3}+2$$