Issolvi sqrt{-2^2}=left|-1right|+1/9*-3^2+sqrt[3]{-8}

$$\sqrt{ { -2 }^{ 2 } } = \left| -1 \right| + \frac{ 1 }{ 9 } \times { -3 }^{ 2 } + \sqrt[ 3 ]{ -8 }$$

Ivverifika

Passi tas-Soluzzjonijiet

Ikkalkula -2 bil-power ta' 2 u tikseb 4.

$$\sqrt{4}=|-1|+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Ikkalkula l-għerq kwadrat ta' 4 u ikseb 2.

$$2=|-1|+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Il-valur assolut ta' numru reali a huwa a meta a\geq 0, jew -a meta a<0. Il-valur assolut ta' -1 huwa 1.

$$2=1+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Ikkalkula -3 bil-power ta' 2 u tikseb 9.

$$2=1+\frac{1}{9}\times 9+\sqrt[3]{-8}$$

Immultiplika \frac{1}{9} u 9 biex tikseb 1.

$$2=1+1+\sqrt[3]{-8}$$

Żid 1 u 1 biex tikseb 2.

$$2=2+\sqrt[3]{-8}$$

Ikkalkola \sqrt[3]{-8} u ikseb -2.

$$2=2-2$$

Naqqas 2 minn 2 biex tikseb 0.

$$2=0$$

Qabbel 2 u 0.

$$\text{false}$$