Issolvi sqrt{m+1}+(n-3)^2=0

$$\sqrt { m + 1 } + ( n - 3 ) ^ { 2 } = 0$$

Solvi għal m

$$m=-1$$

$$n=3$$

Passi biex Issolvi l-Ekwazzjonijiet Radikali

Naqqas \left(n-3\right)^{2} miż-żewġ naħat tal-ekwazzjoni.

$$\sqrt{m+1}+\left(n-3\right)^{2}-\left(n-3\right)^{2}=-\left(n-3\right)^{2}$$

Jekk tnaqqas \left(n-3\right)^{2} minnu nnifsu jibqa' 0.

$$\sqrt{m+1}=-\left(n-3\right)^{2}$$

Ikkwadra ż-żewġ naħat tal-ekwazzjoni.

$$m+1=\left(n-3\right)^{4}$$

Naqqas 1 miż-żewġ naħat tal-ekwazzjoni.

$$m+1-1=\left(n-3\right)^{4}-1$$

Jekk tnaqqas 1 minnu nnifsu jibqa' 0.

$$m=\left(n-3\right)^{4}-1$$

Naqqas 1 minn \left(n-3\right)^{4}.

$$m=\left(n-4\right)\left(n-2\right)\left(\left(n-3\right)^{2}+1\right)$$

Solvi għal n

$$n=3$$

$$m=-1$$