Issolvi sin(225^circ)=

$$\sin ( 225 ^ { \circ } ) =$$

Evalwa

$$-\frac{\sqrt{2}}{2}\approx -0.707106781$$

Passi tas-Soluzzjonijiet

Uża \sin(x+y)=\sin(x)\cos(y)+\sin(y)\cos(x) fejn x=180 u y=45 biex tikseb ir-riżultat.

$$\sin(180+45)=\sin(180)\cos(45)+\sin(45)\cos(180)$$

Ikseb il-valur ta’ \sin(180) mit-tabella tal-valuri trigonometriċi.

$$0\cos(45)+\sin(45)\cos(180)$$

Ikseb il-valur ta’ \cos(45) mit-tabella tal-valuri trigonometriċi.

$$0\times \frac{\sqrt{2}}{2}+\sin(45)\cos(180)$$

Ikseb il-valur ta’ \sin(45) mit-tabella tal-valuri trigonometriċi.

$$0\times \frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\cos(180)$$

Ikseb il-valur ta’ \cos(180) mit-tabella tal-valuri trigonometriċi.

$$0\times \frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}\left(-1\right)$$

Agħmel il-kalkoli.

$$-\frac{\sqrt{2}}{2}$$